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Fix repeating task after timeout (#184)
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@@ -0,0 +1,38 @@
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import signal
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from django.utils.translation import gettext_lazy as _
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from django_q.conf import logger
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from .exceptions import TimeoutException
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class TimeoutHandler:
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def __init__(self, timeout: int):
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self._timeout = timeout
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def raise_timeout_exception(self, signum, frame):
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raise TimeoutException(
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f"Task exceeded maximum timeout value ({self._timeout} seconds)"
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)
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def __enter__(self):
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# if the timeout is -1, then there is no timeout and the task will always keep running until it's done or manually killed
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if self._timeout == -1:
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return
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try:
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signal.signal(signal.SIGALRM, self.raise_timeout_exception)
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except ValueError: # ValueError is raised for Windows users
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logger.debug(_("SIGALARM is not available on your platform"))
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signal.alarm(self._timeout)
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def __exit__(self, exc_type, exc_value, traceback):
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if self._timeout == -1:
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return
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"""When getting out of the timeout, reset the alarm, so it won't trigger"""
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try:
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signal.alarm(0)
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signal.signal(signal.SIGALRM, signal.SIG_DFL)
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except ValueError: # ValueError is raised for Windows users
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logger.debug(_("SIGALARM is not available on your platform"))
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